Question

When `4.215 g` of a metallic carbonate was heated in a hard glass tube, the `CO_(2)` evolved was found to measure `1336 mL` at `27^(@)C` and `700 mm` pressure. What is the equivalent weight of the metal?

Answer 1

`PV=nRT=(w)/(M)RT`
or `(700)/(760)xx(1336)/(1000)=(w)/(44)xx0.0821xx300`
or `w=2.198 g CO_(2)`
Molecular mass of any meteal carbonate is `2E+60`, where `E` is the equivalent mass of the metal. So
`(2E+60)/(4.215)=(44)/(2.198)`
or `E=12.188 g`