100 g of `H_2O_2` solution contains `x g of H_2O_2`
`="Weight" of H_2O_2`
`m" Eq of "H_2O_2=("Weight" of H_2O_2xx10^(3))/(EwH_2O_2)`
`=(5.1x)/(100)xx(1)/(17)xx10^(3)=3x mEq`
`Cr_2O_7^(2-)-=H_2O_2`
`mEq-=mEq`
`N_1V_1(mL)-=3x`
`N_1xx x mL =3x`
`N(K_2Cr_2O_7)=3N`
`M(K_2Cr_2O_7)=(N)/(n)=0.5M`