Question

1.67 g mixture of Al and Zn was completely dissolved in acid and evolved 1.69 L of `H_2` at STP. Calculate the weight Al and Zn in the mixture.

Answer 1

Let x and y be the weights of Al and Zn in the mixture.
`x+y=1.67` .. (i)
" Eq of "`Al+Eq` of `Zn= Eq` of `H_2`
`((a)/((27)/(3))+(b)/((65)/(2)))=(1.69)/((22.4)/(2)) ` …(ii)
Solving equation (i) and (ii) we get
`x=1.25 g`
`y=0.42`