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What is the charge involved when 0.1 " mol of "`C_6H_5NO_2` is reduced to `C_6H_5` NHOH?

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What is the charge involved when 0.1 " mol of "`C_6H_5NO_2` is reduced to `C_6H_5` NHOH?
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`C_6H_5NO_2+4e^(-)tounderset(C_6H_5NO)(C_6H_5NH_2O)`
`4xx6+5+x-4=0`
`24+7+x-2=0`
`x=-29`
`n=-25-(-29)=4`
`1 mol =4F or 0.1 mol =0.4F`
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