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What is the oxidation number of `Xe` in `XeOF_(2)`?
A. zero
B. `+2`
C. `+4`
D. `+3`

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Correct Answer - C
Oxidation no of Xe in `XeOF_(2)`
`overset(x)Xeoverset(-2)Ooverset(-1)F_(2)=0`
or x-4 =0 or x=+4

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