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The oxidation states of the most elecrtronegative element in the products of rection between `BaO^(2)` and diluent `H_(2)SO_(4)` are:

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The oxidation states of the most elecrtronegative element in the products of rection between `BaO^(2)` and diluent `H_(2)SO_(4)` are:
A. `-1`
B. `+1`
C. `-2`
D. 0
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Correct Answer - A::C
`BaO_(2)+H_(2)SO_(4)+H_(2)SO_(4)rarrBaSO_(4)+H_(2)O_(2)`
Oxidation state of O in `BaSO_(4)`=-2 "and in" H_(2)O_(2)`=-1`
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