Correct Answer - A
`(6e^(-)+Cr_(2)O_(7)^(2-)rarr2Cr^(3+))`
`Sn^(2+)rarrSn^(4+)+2e^(-)`
Equivalent of `Cr_(2)O_(7)^(2-)= "Equivalent of" Sn^(2+)`
`(n=6)` , `(n=2)`
`implies1 Eq= 1Eq`
`(1)/(6) mol =(1)/(2) mol`
`(1)/(3) "mol of" Cr_(2)O_(7)^(2-)= 1 "mol of" Sn^(2+)`.