Correct Answer - A
In one oxide:
`50g` of element combines with `50 g` of oxygen.
Therefor, `1 g` of element will combine with `1 g` of oxygen
In the other oxide:
`40 g` of element will combine with `60 g` of oxygen.
Therefore, `1 g` of element will combine with `64//40` or `1.5 g` of oxygen.
Thus, the weights of oxygen that combines with `1 g` of the element in the two oxides are in the ratio of `1 : 1.5` or `2:3,` which is a simple ratio. This illustrates the law of multiple proportions.