Question

A sugar syrup of weight `214.2 g` contains `34.2 g` of sugar `(C_(12) H_(22) O_(11))`. Calculate
a. the molal concentration.
b. the mole fraction of the sugar in the syrup.

Answer 1

Correct Answer - A::B
Weight of solvent `= 214. 2 - 34.2 = 180 g`
`m = (W_(2) xx 1000)/(Mw_(2) xx W_(1)) = (34.2 xx 1000)/(342 xx 180) = 0.555`
b. `chi_(2) = (n_(1))/(n_(1) + n_(2)) = (34.2//342)/((180)/(18) + (34.2)/(342)) = 0.0099`