Question

`3KClO_(3)+3H_(2)SO_(4)rarr3KHSO_(4)+HClO_(4)+2ClO_(2)+H_(2)O`
Equivalent weight of `KClO_(3)` is
A. `(M)/(4)`
B. `(M)/(2)`
C. `(M+(M)/(2))`
D. `((M)/(4)+(M)/(2))`

Answer 1

Correct Answer - C
Disproportionation reaction
`ClO_(3)^(ө)rarrClO_(4)^(ө)+2e^(-)(x=2)` (oxidation)
`x-6= -1, x-8= -1`
`x=5 , x=7`
`e^(-)+ClO_(3)^(ө)rarrClO_(2), (x=1)` (reduction)
`x=5, x= -4= 0`
`x=4`
`Ew=M+(M)/(2)`