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What weight of a metal of equivalent weight 12 will give `0.475 g` of its chloide?
A. `0.12 g`
B. `0.24 g`
C. `0.36 g`
D. `0.48 g`

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Correct Answer - A
`Ew` of metal chloride `= Ew "of" M + Ew "of" Cl`
`= 12 + 35.5 = 47.5`
`47.5 g` of metal chlofide `implies` weight of metal `implies 12 g`
`0.475 g` of metal chloride `implies (12 xx 0.475)/(47.5)`
`implies 0.12 g`

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