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The molarity of `H_(2)SO_(4)` is `18 M`. Its density is `1.8 g mL^(-1)`.
A. 36
B. 200
C. 500
D. 18

1 Answer

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Best answer
Correct Answer - C
Use formula
`d = M ((Mw_(2))/(1000) + (1)/(m)) implies 1.8 = 18 ((98)/(1000) + (1)/(m))`
solve for `m:`
`:. M = 500`

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