Hypotenuse of first right triangle
\(\sqrt{1^2+1^2}=\sqrt{1+1}=\sqrt{2}\)
Hypotenuse of second right triangle
\(\sqrt{\sqrt{2^2}+1^2}=\sqrt{2+1}=\sqrt{3}\)
Hypotenuse of third right triangle
\(\sqrt{\sqrt{3^2}+1^2}=\sqrt{3+1}=\sqrt{4}=2\)
Hypotenuse of fourth right triangle
\(\sqrt{2^2+1^2}=\sqrt{4+1}=\sqrt{5}\)
i. e. the length of one side of square is \(\sqrt{5}\)
Area \(\sqrt{5}\times\sqrt{5}\) = 5 sq. m
