a. 1 mole of `N_(2) implies 28 g = 22.4 L` at `STP`
`14 g = 11.2 L`
b. 1 mole of `NH_(3) = 17 g`
`= 6.023 xx 10^(23)` molecules `= 2.24 L`
`:. 6.023 xx 10^(22)` molecules `= 2.24 L`
c. 1 mol of `SO_(2) = 32 + 16 xx 2 = 64 g = 22.4 L`
0.1 mole of `SO_(2) = 2.24 L`