Question

Upon heating `KClO_(3)` in the presence of catalytic amount of `MnO_(2)`, a gas W is formed. Excess amount of W reacts with white phosphorus to give X. The reaction of X with pure `HNO_(3)` gives Y and Z.
W and X are, respectively
A. `O_(2)andP_(4)O_(6)`
B. `O_(2)andP_(4)O_(10)`
C. `O_(3)andP_(4)O_(6)`
D. `O_(3)andP_(4)O_(10)`

Answer 1

Correct Answer - B
`2KClO_(3)overset(MnO_(2),Delta)to2KCl+underset((W))(3O_(3))`
`P_(4)+10O_(2)overset("Oxidation")tounderset((X))(P_(4)O_(10))`
`P_(4)O_(10)` acts as dehydrating agent and removes `H_(2)O` from `HNO_(3)` to give `N_(2)O_(5)` (Y) and itself gets converted into `HPO_(3)` (Z).
Thus, X is `P_(4)O_(10)` Y is `N_(2)O_(5)`, and Z in `HPO_(3)` and W is `O_(2)`.
`P_(4)O_(10)+4HNO_(3)tounderset((Y))(2N_(2)O_(5))+underset((Z))(4HPO_(3))`