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A metal `M` of atomic weight 54.9 has a density of `7.42 g cm^(-3)`. Calculate the volume occupied and the radius of the atom of this metal assuming it to be sphere.

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Correct Answer - A::B::C::D
Mass of 1 atom of metal `M = (54.94)/(6.023 xx 10^(23))`,
`V = (54.94)/(6.023 xx 10^(23) xx 7.42) = 1.3 xx 10^(23) cm^(3)`
`V = (4)/(3) pi r^(3) implies 1.23 xx 10^(4)/(3) pi r^(3)`
`:.r = 1.42 xx 10^(-8) cm`

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