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If `K_(sp)` for `HgSO_(4)` is `6.4xx10^(-5)`, then solubility of this substance in mole per `m^(3)` is
A. `8xx 10^(-6)`
B. `8XX 10^(-3)`
C. `4.6 xx 10^(-5)`
D. None of these

1 Answer

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Best answer
Correct Answer - B
`S= (K_(sp))^(1//2) =(6.4 xx 10^(-5))^(1//2)`
`=(64 xx 10^(-6))^(1//2) =8 xx 10^(-3).`

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