Question

The value of `DeltaG^(ɵ)` for the phosphorylation of glycose in glycolysis is `13.8 kJ mol^(-1)`. Find the value of `K_(c)` at `298 K`

Answer 1

`Delta G^(Theta) =- 2.303 RT log K or log K =- (Delta G^(Theta))/(2.303 RT)`
`Delta G^(Theta) = 13.8 Kj mol^(-1) , R = 8.314 J K^(-1) mol^(-1) , T =298 K`
`log K = - ((13.8xx 10^(3) J mol^(-1)))/(2.303 xx(8.314 J K^(-1) ) xx (298 K)) =- 2.4185 = overset(-)(3).5815`
`K= Antilog "("overset(-)(3).5815")"=3.815 xx 10^(-3)`