Question

Given the equilibrium , `N_(2)O_(4)(g) hArr 2NO_(2) (g) " with " k_(p) =0.15 " atm at " 298 K.`
(a) What is `K_(p)` using pressure in torr?
(b) What is `K_(c)` using units of moles per litre ?

Answer 1

`(a) K_(p) = ((760 " torr" ) xx (0.15 atm))/ ((1 atm)) = 1.14 xx 10^(2) " torr "`
`(b) K_(p) = K_(c)(RT)^(Deltan)`
`K_(C) = (K_(p))/(RT)^(Deltan)=((0.15 atm))/((0.0821 " L atm K"^(-1) " mol"^(-1) xx 298 K)^(2-1))=6.13 xx 10^(-3) "mol"^(-1)`