Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
84 views
in Chemistry by (73.8k points)
closed by
A solution of `CoCI_(2).6H_(2)O` in isopropyl alcohol and water is purple. The color change to blue when we add
A. concentrated HCI
B. `AgNO_(3)(aq.)
C. both (1) and (2)
D. none of these

1 Answer

0 votes
by (74.1k points)
selected by
 
Best answer
Correct Answer - A
The purple color is due to the mixture of `[Co(H_(2)O)_(6)]^(2+)` (pink) and `[CoCl_(4)]^(2-)` (blue):
`[Co(OH_(2))_(6)]^(2+)+4Cl^(-)hArr[CoCl_(4)]^(2-)+6H_(2)O`
When we add concentrated HCI, excess `Cl^(-)` shifts the equilibrium to the right (blue). Adding `AgNO_(3)` (aq.) removes some `Cl^(-)` by precipitation of `AgCl(s)` and favours the reaction to the left (produces more `[Co(OH_(2))_(6)]^(2+)` and the resulting solution is pink.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...