Calculate the `pOH` of solution at `25^(@)C` that contains `1xx10^(-10) M` of hydronium ions, i.e., `H_(3)O^(+)`

Correct Answer - C
`C_(H_(3)O^(+))=10^(-pH) mol L^(-1)`
`=10^(-10)mol L^(-1)`
`:. pH = 10`
Now, for any aqueous solution at `25^(@)C`,
`pH+pOH=14`
`:. pOH=14-pH`
`=14-10`
`=4`

Calculate the `pOH` of solution at `25^(@)C` that contains `1xx10^(-10) M` of hydronium ions, i.e., `H_(3)O^(+)`

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