Question

When sulphur in the form of `S_(8)` is heated at 900 K , the intial pressure of 1 atm falls by 29% at equilibrium . This is because of conversion of `S_(8) "to" S_(2)` . Calculate the equilibrium constant for the reaction.

Answer 1

` {:(,S_g(g),hArr,4S_(2)(g)), (" Intial",1 atm,,), (" At eqm.",1-0*29 = 0*71 "atm",,4b xx 0*29 "atm" = 1*16 "atm"):} `
` K_(p) = (p_(s_(2)(g))^(4))/(p_(s_(g(g))))= (1*16 " atm ")^(4)/(0*71 "atm" )=2*55 " atm "^(3)`