Molar volume of a gas, i.e., volume of 1 mole of the gas =22.7 L at STP
1 mole of CO=28 g, i.e., 28 g of CO have volume =22.7 L at STP
`:.` 1 g of CO will have volume `=(22.7)/(28)` L at STP
Similarly, `" "1 g of H_(2)O" vapour"=(22.7)/(18)`L, 1 g `CH_(4)=(22.7)/(16)"L",1 g NO=(22.7)/(30)"L"`
Thus, 1 g of `CH_(4)` will occupy maximum volume and 1 g of NO will occupy minimum volume at STP.