Question

A sealed tube which can withstand a pressure of 3 atmosphere is filled with air at `27^(@)C` and 760 mm pressure. Find the temperature above which it will burst.

Answer 1

Let the volume of air in the tube be V mL.
`{:("Initial conditions","Final conditions"),(V_(1)=V mL,V_(2)=V mL),(P_(1)=760 mm=1 atm,P_(2)=3" atm"),(T_(1)=273+27=300 K,T_(2)=?):}`
By Applying gas equation, we have
`(Vxx1)/(300)=(Vxx3)/(T_(2))" ":. T_(2)=300xx3=900 K`
Thus, the temperature above which the tube will burst`=900-273=627^(@)C`