Correct Answer - A::B::C::D
`c=sqrt((3RT)/(M))" or "sqrt((3RT)/(M))=c^(2)" or "T=(c^(2)xxM)/(3R)=((1500" m s"^(-1))^(2)(32xx10^(-3)kg mol^(-1)))/(3xx8.314" kg m"^(2)s^(-1))=2886.7 K`
`bar c=sqrt((8RT)/(piM))" or " T=(bar c^(2)xxpixxM)/(8R)=((1500)^(2)(3.14)(32xx10^(-3)))/(8xx8.314)=3399 K`
`c^(**)=sqrt((2RT)/(M))" or "T=(c^(**2)M)/(2R)=((1500)^(2)(32xx10^(-3)))/(2xx8.314)=4330 K`.