Question

A `4:1` mixture of helium and methane is contained in a vessel at 10 bar pressure. Due to a hole in the vessel, the gas mixture leaks out. The composition of the mixture effusing out initially is
A. `8:1`
B. `8:3`
C. `4:1`
D. `1:1`

Answer 1

Correct Answer - A
Pressure of helium=8 bar
Pressure of `CH_(4)=2` bar
`(r_(He))/(r_(CH_(4)))=(P_(1))/(P_(2))sqrt((M_(CH_(4)))/(M_(He)))=(8)/(2)sqrt((16)/(2))=(8)/(1)=8:1`