Correct Answer - b
In `SO_(2)` molecule , S is `sp^(2)`-hybridized
(a) `CO_(2) H = (1)/(2) (4+0) = 2 implies C is sp` hybridized
(b) `SO_(2) H = (1)/(2) (6+0) = 3 implies S is sp^(2)` hybridized
(c) `NO_(2)^(+)H H = (1)/(2) (5-1) = 2 implies N `is `sp` hybridized
(d) `CO H = (1)/(2) (4+0) = 2 implies C is sp^(3)` hybridized