Correct Answer - D
`O_(2) = 16` electrons . M.O. configuration is
` KK sigma (2s)^(2) sigma^(**)(2s)^(2)sigma (2p_(z))^(2) pi (2p_(x))^(2) pi(2p_(y))^(2)`
`pi^(**) (2p_(x))^(1) pi^(**) (2p_(y))^(1) ` (paramagnetic)
`B_(2) = 10 ` electrons. M. O. configuration is
`KK sigma (2s)^(2) sigma^(**)(2s)^(2) pi (2p_(x))^(1) pi(2p_(y))^(1)` (paramagnetic)
NO = 15 electrons .M.O. configuration is
`KK sigma (2s)^(2) sigma^(**)(2s)^(2) sigma (2p_(z))^(2) pi (2p_(x))^(2) pi (2p_(y))^(2)`
`pi^(**)(2p_(x))^(1) `
CO = 14 electrons . M.O. configuration is
`KK sigma (2s)^(2) pi(2p_(x))^(2)pi(2p_(y))^(2) sigma (2p_(z))^(2) sigma ^(**) (2s)^(2)`
(diamagnetic)
