Correct Answer - B::C
In `BrF_(5),Br` has 7 valence electrons ,five are shared
with five F atoms . Hence, lone pair =1
In`CIF_(3)` Cl has 7 valence electrons, three are
shared with three F atom, lone pairs =2.
In`XeF_(4)`,Xe has 8 valence electrons, four are
shared with four F atoms, lone pairs =2
In`SF_(4),S` has 6 valence electrons, four are shared
with four F atoms, lone pair =1