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Calculate the percent ionic character of HCL . Given that the observed dipole
moment is 1 . 0 3 D and bond length of HCl is 1 .275 Å`.

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If HCl were 100% ionic and would carry charge equal to one unit, viz, ` 4.8 xx10^(-10)` esu. As
bond length of HCl is ` 1.275 Å` , its dipole moment for 100% ionic character would be
`mu_("ionic") = qxxd = 4.8xx10^(10) esu xx 1.275xx10^(-8) cm = 6 . 12 xx10^(18)` "esu cm "= 6.12 D
`mu_("observed")= 1 . 0 3 D ("Given")`
` therefore % ` ionic character = `(mu_("observed"))/(mu_("ionic"))xx 100 = (1.03)/(6.12) xx100 = 16.83 %`

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