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Can we have a diatomic molecule with its ground state moleculer orbitals full with electrons ? Give
a reason for your answer .

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No. Because bond order becomes zero, e.g., in case of `He_(2), Be_(2), Ne_(2)` , etc . Note that in `H_(2), sigma _(1s)` M.O. is full
but `sigma_(1s)^(**)` is empty .

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