Question

The correct order of bond order values among the following :
`A . NO^(-) B.NO^(+) C.NO D.NO^(2+) E. NO^(2-)` is
A. `A lt D lt C lt B lt E`
B. `D = B lt A lt E le C `
C. `E lt A lt D = C lt B`
D. `B lt C lt D lt A lt E `

Answer 1

Correct Answer - C
`NO=KK sigma_(2)^(2) sigma_(2s)^(**2) sigma_(2p_(z))^(2) pi_(2p_(x))^(2)pi_(2p_(y))^(2)pi_(2p_(x))^(**1)`
B.O. `= (1)/(2) (8-3) = (5)/(2) = 2.5 `
`NO^(-)=KK sigma_(2)^(2) sigma_(2s)^(**2) sigma_(2p_(z))^(2) pi_(2p_(x))^(2)pi_(2p_(y))^(2)pi_(2p_(x))^(**1)pi_(2p_(y))^(**1)`
B.O. = `(1)/(2) (8-4)= 2`
`NO^(2-)=KK sigma_(2)^(2) sigma_(2s)^(**2) sigma_(2p_(z))^(2) pi_(2p_(x))^(2)pi_(2p_(y))^(2)pi_(2p_(x))^(**2)pi_(2p_(y))^(**1)`
B.O. = `(1)/(2) (8-5) = (3)/(2) = 1.5 `
`NO^(+)=KK sigma_(2)^(2) sigma_(2s)^(**2) sigma_(2p_(z))^(2) pi_(2p_(x))^(2)pi_(2p_(x))^(2)pi_(2p_(y))^(2)`
B.O. `= (1)/(2) (8-2) = 3 `
`NO^(2+)=KK sigma_(2)^(2) sigma_(2s)^(**2) sigma_(2p_(z))^(2) pi_(2p_(x))^(2)pi_(2p_(y))^(1)`
B.O. ` = (1)/(2) (7-2) = (5)/(2) = 2.5 `
Thus `NO^(2-) lt NO^(-) NO = NO^(2-) lt NO^(+)`,
i.e. `E lt A lt C = D lt B `