An organic compound `X(C_(6)H_(13)Br)` is optically active, `X` on treatment with `(CH_(3))_(3)COK` in `(CH_(3))_(3)COH` gives `Y(C_(6)H_(12))`, a major product. `Y` on treatment with `Br_(2) - C Cl_(4)` in the presence of `FeBr_(3)` gives a dibromide which on further treatment with `NaNH_(2)` gives `C_(6)H_(10)` which is still optically active. Hence, `X` and `Y` respectively are
A.
B.
C.
D.