Data : f1 = 60 rpm = 60/60 rot/s = 1 rot/s, f2 = 30 rpm = 30/60 rot/s =1/2 rot/s, ∆E = — 100 J
(i)
![](https://www.sarthaks.com/?qa=blob&qa_blobid=6246373525466104381)
![](https://www.sarthaks.com/?qa=blob&qa_blobid=11660665766476383035)
This gives the MI of the flywheel about the given axis.
(ii) Angular momentum, L = Iω = I(2πf) = 2πIf The change in angular momentum, ∆L
= L2 – L1 = 2πI(f2 – f1)
= 2 × 3.142 × 6.753(\(\cfrac{1}{2}\)– 1)
= -3.142 × 6.753 = -21.22 kg.m2 /s