Consider a horizontal constricted tube. Let A1 and A2 be the cross-sectional areas at points 1 and 2, respectively. Let v1 and v2 be the corresponding flow speeds, ρ is the density of the fluid in the pipeline. By the equation of continuity,
v1A1 = v2 A2 …… (1)
\(\therefore\) \(\cfrac{v_2}{v_1} = \cfrac{A_1}{A_2}\)> 1(\(\because\) A1 > A2)
Therefore, the speed of the liquid increases as it passes through the constriction. Since the meter is assumed to be horizontal, from Bernoulli’s equation we get,
Again, since A1 > A2 , the bracketed term is positive so that p1 > p2 . Thus, as the fluid passes through the constriction or throat, the higher speed results in lower pressure at the throat.