Molar enthalpy of combustion of `C_(2)H_(2)(g),C_("graphite")andH_(2)(g)` are -1300,-394, and -286 KJ/mole respectively , then , Calculate Bond enthalpy of `C-=C` bond inKJ /mole:
`"Given" : DeltaH_("sub") (C_("graphite"))=715 KJ//"mole"`
`DeltaH_(BE)(H-H)=436 KJ//"mole" `
`DeltaH_(BE)(C-H)=413KJ//"mole"`
A. 415
B. 610
C. 1215
D. 814