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A reaction attains equilibrium state under standard conditions, then what is incorrect for this?
A. Equilibrium constant K = 0
B. Equilibrium constant K = 1
C. `DeltaG^(@)=0 and DeltaH^(@)=TDeltaS^(@)`
D. `DeltaS=0 and DeltaH=TDeltaS`

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Correct Answer - A
`DeltaG^(@)=0` at equilibrium under standard state.
Also, at equilibrium, `DeltaG=0`
Also, `DeltaG^(@)=2.303RT logK`
`therefore" K=1`

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