`2(Ag)toB(g), deltaH=-20kcal//mol`. In a closed rigid container, 0.2mole of `A(g)` at constant temperature `727^(@)C` convert into B(g) then, change in heat energy in the process will be:
`(R=2cal//"mole"-K)`
A. `-12kcal`
B. `-1.8kacl`
C. `-2.4kcal`
D. `0.24kcal`