Correct Answer - B
In an exothermic reaction, heat is evolved and system loses heat to the surrounding. Therefore, `q_(p)` will be negative and hence `DeltaH` will be negative `[because q_(p)=H_(2)-H_(1)=DeltaH]`. Similarly, in an endothermic reaction heat is absorbed, `q_(b)` is positive hence, `DeltaH` will be positive.