Correct Answer - `2091.32 kJ mol^(-1)`
following equation can be obtained from the avilable data
(i) `C (s) + O_(2) (g) rarr CO_(2) (g) , Delta H = 393.5 kJ`
(ii) `H_(2) (g) + (1)/(2) O_(2) (g) rarr H_(2) O (l) , Delta H = 2858 kJ`
(iii) `3C (s) + 3H_(2) (g) rarr C_(2)H_(6) (g), Delta H = + 20.42 kJ`

`(g) rarr C_(3) H_(6) (g) , Delta H = -33.0 kJ`
The desired equation is
`(g) + (9)/(2) O_(2) (g) rarr 3 CO_(2) (g) + 3H_(2)O(l), Delta H = 2091.32 kJ mol^(-1)`
To get the desired equation compute as follows `[3 xx (i) + 3 xx (ii) ] + (vi) - (iii)]`
`(g) + (9)/(2)O_(2) (g) rarr 3CO_(2) (g) + 3H_(2)O (l)`,
`Delta H = 2091.32 kJ mol^(-1)`