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`DeltaU^(Θ)` of combustion of methane is `-XkJ mol^(-1)`. The value of `DeltaH^(Θ)` is
A. `=DeltaU^(Ө)`
B. `gtDeltaU^(Ө)`
C. `ltDeltaU^(Ө)`
D. `=0`

1 Answer

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Best answer
Since `DeltaH^(theta)=DetlaU^(theta)+Deltan_(g)RT and DeltaU^(theta)=-XkJ "mol"^(-1)`
`DeltaH^(theta)=(-X)+Deltan_(g)RT.`
`rArrDeltaH^(theta)ltDetlaU^(theta)`
Therefore, alternative (iii) is correct.

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