Question

For the equilibrium,
`PCI_(5)(g) hArr PCI_(3)(g) +CI_(2)(g) at 25^(@)C K_(c) =1.8 xx 10^(-7)`
Calculate `DeltaG^(Theta)` for the reaction `(R = 8.314 J K^(-1) mol^(-1))`.

Answer 1

We know,
`DeltaG^(Theta) =- 2.303 RT log_(10)K_(c)`
`=- 2.303 xx 8.314 xx 298 log (1.8 xx 10^(-7))`
`= 38484 J mol^(-1) = 38.484 kJ mol^(-1)`