Question

`C_(2)H_(4) +CI_(2) rarr C_(2)H_(4)CI_(2)`
`DeltaH =- 270.6 kJ mol^(-1)K^(-1), DeltaS =- 139 J`
a. Is the reaction favoured by entropy, enthalpy both or none?
b. Find `DeltaG` if `T = 300K`.

Answer 1

a. Since `DeltaH =- ve`, exothermic process and is favoured, i.e., it will be spontaneous.
b. `DeltaG = DeltaH - T DeltaS`
`=- 270.6 xx 1000 - 300 xx (-139)`
`=- 228900 J =- 228.9 kJ`