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Given that:
i. `C(s) + O_(2)(g) rarr CO_(2)(g) , DeltaH =- 94.05 kcal`
ii. `H_(2)(g) +(1)/(2) O_(2)(g) rarr H_(2)O(l), DeltaH =- 68.32 kcal`
iii. `C_(2)H_(2)(g) +(5)/(2) O_(2)(g) rarr 2CO_(2)(g) +H_(2)O(l),DeltaH =- 310.62 kcal`
The heat of formation fo acetylene is
A. `-1802 kJ`
B. `+1802 kJ`
C. `-800 kJ`
D. `+228 kJ`

1 Answer

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Best answer
Required equation is:
`2C(s) + H_(2)(g) rarr C_(2)H_(2)(g)`
`2 xx (i) +(ii) - (iii)` gives
`DeltaH = 2 xx (-94.05) - 68.32 -(-310.62)`
`=- 188.1 - 68.32 + 310.62`
`=- 54.2 kcal`

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