Question

A mono-atomic gas `X` and an diatomic gas `gamma` both initially at the same temperature and pressure are compressed adiabatically from a volume `V` to `V//2`. Which gas will be at higher temperature?
A. `X`
B. `Y`
C. both are same
D. Cannot be determined

Answer 1

`T_(1)V_(1)^(gamma-1) = T_(2)V_(2)^(gamma -1)`
`:. (T_(2))/(T_(1)) = ((V_(1))/(V_(2)))^(gamma-1) = 2^(gamma-1)`
Since `gamma` is more for the gas `X`, the temperature will also be more for it.