Correct Answer - `DeltaH = - 122. 56 kJ mol^(-1) , DeltaU = - 125. 04kJ mol^(-1)`
`NH_(4)NO_(3)(s) rarrN_(2)O(g) + 2H_(2)O(l), DeltaH _("reaction") = SigmaDelta_(f) H (` Products `) -SigmaDelta_(f) H (` Reactants)
`Deltan_(g) =n_(p)- n_(r) = 1-0 = 1`
`DeltaU = DeltaH - Delta n_(g) RT`