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The ionic radii of `A^+` and `B^-` ions are `0.92xx10^(-10)` m and `1.81xx10^(-10)` m . The coordination number of each ion in AB is
A. 2
B. 6
C. 4
D. 8

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Best answer
Correct Answer - B
Radius ratio , `r_(+)/r_(-)=(0.98xx10^(-10))/(1.81xx10^(-10))=0.541`
It lies in the range 0.414-0.732 . Hence, coordination number of each ion will be 6, as in the case of NaCl

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