Question

The maximum number of electrons that can have principal quantum number, n = 3, and spin quantum number, `m_(s) = -(1)/(2)`, is

Answer 1

Correct Answer - 9
Number of orbitals in the shell with n = 3 will be `= n^(2) = 3^(2) = 9`. Each orbital can have maximum 2 electrons one with spin `+(1)/(2)` and the other with `- (1)/(2)`. Hence, number of electrons with `m_(s) = - (1)/(2)` will be 9