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Calculate the number of protons, neutrons and electrons in `._(35)^(80)Br`.

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Here, Z = 35, A = 80
`:.` No. of protons = Atomic No. = 35
No. of neutrons `= A - Z = 80 - 35 = 45`
As the atom is neutral, No. of electrons = No. of protons = 35

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