Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
535 views
in Chemistry by (70.3k points)
closed by
`A_(2)B` molecules`(" molar mass " = 259.8 g//"ml")` crystallises in a hexagonal lattice as shown in figure .The lattic constants were `a=5 Å` and `b=8 Å` . If denstiy of crystal is `5 g//cm^(3)` then how many molecules are contained in given unit cell ? `(" Use" N_(A) = 6xx10^(23))`
image
A. 6
B. 4
C. 3
D. 2

1 Answer

0 votes
by (67.2k points)
selected by
 
Best answer
Correct Answer - D
Volt. Of unit cell `=a^(2) sin 60^(@)xxb=173.2xx10^(-24)cm^(3)`
`a=5overset(@)A`
Mass of unti cell=
`173.2xx10^(-24)xx5xx6xx10^(23)=519.6g`
No. of molecules present in given unit cell `=(519.6)/(259.8)=2`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...